23120001310013 has 2 divisors, whose sum is σ = 23120001310014. Its totient is φ = 23120001310012.

The previous prime is 23120001309961. The next prime is 23120001310031. The reversal of 23120001310013 is 31001310002132.

Together with next prime (23120001310031) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 14219815020889 + 8900186289124 = 3770917^2 + 2983318^2 .

It is a cyclic number.

It is not a de Polignac number, because 23120001310013 - 2¹⁴ = 23120001293629 is a prime.

It is a super-2 number, since 2×23120001310013² (a number of 28 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 23120001309973 and 23120001310000.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (23120001318013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11560000655006 + 11560000655007.

It is an arithmetic number, because the mean of its divisors is an integer number (11560000655007).

Almost surely, 2^{23120001310013} is an apocalyptic number.

It is an amenable number.

23120001310013 is a deficient number, since it is larger than the sum of its proper divisors (1).

23120001310013 is an equidigital number, since it uses as much as digits as its factorization.

23120001310013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 23120001310013 its reverse (31001310002132), we get a palindrome (54121311312145).

The spelling of 23120001310013 in words is "twenty-three trillion, one hundred twenty billion, one million, three hundred ten thousand, thirteen".