Base | Representation |
---|---|
bin | 100001101001001110101… |
… | …001111001111110111111 |
3 | 22012000201002111101111012 |
4 | 201221032221321332333 |
5 | 300340000033413003 |
6 | 4530042413145435 |
7 | 326015545601063 |
oct | 41511651717677 |
9 | 8160632441435 |
10 | 2312012013503 |
11 | 811578564675 |
12 | 31410018b27b |
13 | 13a038b7297a |
14 | 7dc8b059aa3 |
15 | 40219ed18d8 |
hex | 21a4ea79fbf |
2312012013503 has 4 divisors (see below), whose sum is σ = 2312670522288. Its totient is φ = 2311353504720.
The previous prime is 2312012013461. The next prime is 2312012013541. The reversal of 2312012013503 is 3053102102132.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2312012013503 - 236 = 2243292536767 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2312012013403) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 329249126 + ... + 329256147.
It is an arithmetic number, because the mean of its divisors is an integer number (578167630572).
Almost surely, 22312012013503 is an apocalyptic number.
2312012013503 is a deficient number, since it is larger than the sum of its proper divisors (658508785).
2312012013503 is an equidigital number, since it uses as much as digits as its factorization.
2312012013503 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 658508784.
The product of its (nonzero) digits is 1080, while the sum is 23.
Adding to 2312012013503 its reverse (3053102102132), we get a palindrome (5365114115635).
The spelling of 2312012013503 in words is "two trillion, three hundred twelve billion, twelve million, thirteen thousand, five hundred three".
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