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231201223 = 1121018293
BaseRepresentation
bin11011100011111…
…01100111000111
3121010001020110021
431301331213013
5433141414343
634535240011
75505115021
oct1561754707
9533036407
10231201223
111095639a0
1265519007
1338b8cc76
14229c5011
151546e0ed
hexdc7d9c7

231201223 has 4 divisors (see below), whose sum is σ = 252219528. Its totient is φ = 210182920.

The previous prime is 231201203. The next prime is 231201227. The reversal of 231201223 is 322102132.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-231201223 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 231201197 and 231201206.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (231201227) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10509136 + ... + 10509157.

It is an arithmetic number, because the mean of its divisors is an integer number (63054882).

Almost surely, 2231201223 is an apocalyptic number.

231201223 is a deficient number, since it is larger than the sum of its proper divisors (21018305).

231201223 is a wasteful number, since it uses less digits than its factorization.

231201223 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 21018304.

The product of its (nonzero) digits is 144, while the sum is 16.

The square root of 231201223 is about 15205.3024632856. The cubic root of 231201223 is about 613.7573542451.

Adding to 231201223 its reverse (322102132), we get a palindrome (553303355).

Subtracting 231201223 from its reverse (322102132), we obtain a palindrome (90900909).

The spelling of 231201223 in words is "two hundred thirty-one million, two hundred one thousand, two hundred twenty-three".

Divisors: 1 11 21018293 231201223