Base | Representation |
---|---|
bin | 100001101001100101110… |
… | …010011011000010011101 |
3 | 22012001201010210100021110 |
4 | 201221211302123002131 |
5 | 300341243412401023 |
6 | 4530145115452233 |
7 | 326031300504552 |
oct | 41514562330235 |
9 | 8161633710243 |
10 | 2312400122013 |
11 | 811757648303 |
12 | 3141aa157079 |
13 | 13a09b3ac787 |
14 | 7dcc6806a29 |
15 | 4023e0e6a93 |
hex | 21a65c9b09d |
2312400122013 has 128 divisors (see below), whose sum is σ = 3510681108480. Its totient is φ = 1347010560000.
The previous prime is 2312400122003. The next prime is 2312400122023. The reversal of 2312400122013 is 3102210042132.
It is an interprime number because it is at equal distance from previous prime (2312400122003) and next prime (2312400122023).
It is not a de Polignac number, because 2312400122013 - 29 = 2312400121501 is a prime.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2312400122003) by changing a digit.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 668901981 + ... + 668905437.
It is an arithmetic number, because the mean of its divisors is an integer number (27427196160).
Almost surely, 22312400122013 is an apocalyptic number.
It is an amenable number.
2312400122013 is a deficient number, since it is larger than the sum of its proper divisors (1198280986467).
2312400122013 is a wasteful number, since it uses less digits than its factorization.
2312400122013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3739.
The product of its (nonzero) digits is 576, while the sum is 21.
Adding to 2312400122013 its reverse (3102210042132), we get a palindrome (5414610164145).
The spelling of 2312400122013 in words is "two trillion, three hundred twelve billion, four hundred million, one hundred twenty-two thousand, thirteen".
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