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2312602245551 = 13292211524947
BaseRepresentation
bin100001101001110001110…
…101011101100110101111
322012002020020010021122102
4201221301311131212233
5300342202133324201
64530221140005315
7326036303515163
oct41516165354657
98162206107572
102312602245551
11811850750754
1231424599083b
1313a10122b4c0
147dd055bcca3
1540251c2026b
hex21a71d5d9af

2312602245551 has 12 divisors (see below), whose sum is σ = 2579335215912. Its totient is φ = 2061099073824.

The previous prime is 2312602245539. The next prime is 2312602245599. The reversal of 2312602245551 is 1555422062132.

It is not a de Polignac number, because 2312602245551 - 218 = 2312601983407 is a prime.

It is a super-4 number, since 4×23126022455514 (a number of 51 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2312602245851) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 105751541 + ... + 105773406.

It is an arithmetic number, because the mean of its divisors is an integer number (214944601326).

Almost surely, 22312602245551 is an apocalyptic number.

2312602245551 is a deficient number, since it is larger than the sum of its proper divisors (266732970361).

2312602245551 is a wasteful number, since it uses less digits than its factorization.

2312602245551 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 211525018 (or 211524989 counting only the distinct ones).

The product of its (nonzero) digits is 144000, while the sum is 38.

The spelling of 2312602245551 in words is "two trillion, three hundred twelve billion, six hundred two million, two hundred forty-five thousand, five hundred fifty-one".

Divisors: 1 13 29 377 841 10933 211524947 2749824311 6134223463 79744905019 177892480427 2312602245551