2313004031411 has 2 divisors, whose sum is σ = 2313004031412. Its totient is φ = 2313004031410.

The previous prime is 2313004031369. The next prime is 2313004031413. The reversal of 2313004031411 is 1141304003132.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-2313004031411 is a prime.

Together with 2313004031413, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (2313004031413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1156502015705 + 1156502015706.

It is an arithmetic number, because the mean of its divisors is an integer number (1156502015706).

Almost surely, 2^{2313004031411} is an apocalyptic number.

2313004031411 is a deficient number, since it is larger than the sum of its proper divisors (1).

2313004031411 is an equidigital number, since it uses as much as digits as its factorization.

2313004031411 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 2313004031411 its reverse (1141304003132), we get a palindrome (3454308034543).

The spelling of 2313004031411 in words is "two trillion, three hundred thirteen billion, four million, thirty-one thousand, four hundred eleven".