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231314112341202 = 23116735207666089
BaseRepresentation
bin110100100110000100000011…
…011111110110010011010010
31010100000102011012112111000110
4310212010003133312103102
5220304322300224404302
62135544123004502150
766502615224426342
oct6446040337662322
91110012135474013
10231314112341202
11677818450853a0
1221b3a28424a956
139c0ba9a4792c7
14411993c916d22
151bb2026bb2b6c
hexd261037f64d2

231314112341202 has 32 divisors (see below), whose sum is σ = 505435240031040. Its totient is φ = 69991032222720.

The previous prime is 231314112341177. The next prime is 231314112341227. The reversal of 231314112341202 is 202143211413132.

It is an interprime number because it is at equal distance from previous prime (231314112341177) and next prime (231314112341227).

It is a super-3 number, since 3×2313141123412023 (a number of 44 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 231314112341202.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2603788627 + ... + 2603877462.

It is an arithmetic number, because the mean of its divisors is an integer number (15794851250970).

Almost surely, 2231314112341202 is an apocalyptic number.

231314112341202 is a gapful number since it is divisible by the number (22) formed by its first and last digit.

231314112341202 is an abundant number, since it is smaller than the sum of its proper divisors (274121127689838).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

231314112341202 is a wasteful number, since it uses less digits than its factorization.

231314112341202 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5207666778.

The product of its (nonzero) digits is 6912, while the sum is 30.

Adding to 231314112341202 its reverse (202143211413132), we get a palindrome (433457323754334).

The spelling of 231314112341202 in words is "two hundred thirty-one trillion, three hundred fourteen billion, one hundred twelve million, three hundred forty-one thousand, two hundred two".

Divisors: 1 2 3 6 11 22 33 66 673 1346 2019 4038 7403 14806 22209 44418 5207666089 10415332178 15622998267 31245996534 57284326979 114568653958 171852980937 343705961874 3504759277897 7009518555794 10514277833691 21028555667382 38552352056867 77104704113734 115657056170601 231314112341202