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23131531240117 is a prime number
BaseRepresentation
bin1010100001001101110101…
…01100111110001010110101
310000220100112011222002021121
411100212322230332022311
511012441333444140432
6121110251224343541
74605124623253156
oct520467254761265
9100810464862247
1023131531240117
117409033390243
122717067014bb1
13cba3a8cc7cb1
1459d801b3592d
152a1a86aa9197
hex1509bab3e2b5

23131531240117 has 2 divisors, whose sum is σ = 23131531240118. Its totient is φ = 23131531240116.

The previous prime is 23131531240099. The next prime is 23131531240121. The reversal of 23131531240117 is 71104213513132.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 22832093550436 + 299437689681 = 4778294^2 + 547209^2 .

It is a cyclic number.

It is not a de Polignac number, because 23131531240117 - 211 = 23131531238069 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (23131531250117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11565765620058 + 11565765620059.

It is an arithmetic number, because the mean of its divisors is an integer number (11565765620059).

Almost surely, 223131531240117 is an apocalyptic number.

It is an amenable number.

23131531240117 is a deficient number, since it is larger than the sum of its proper divisors (1).

23131531240117 is an equidigital number, since it uses as much as digits as its factorization.

23131531240117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15120, while the sum is 34.

Adding to 23131531240117 its reverse (71104213513132), we get a palindrome (94235744753249).

The spelling of 23131531240117 in words is "twenty-three trillion, one hundred thirty-one billion, five hundred thirty-one million, two hundred forty thousand, one hundred seventeen".