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2313212119037 is a prime number
BaseRepresentation
bin100001101010010110001…
…011111100011111111101
322012010210201201001210022
4201222112023330133331
5300344424300302122
64530401443421525
7326060360406041
oct41522613743775
98163721631708
102313212119037
11812033a32726
123143960848a5
1313a19a6a31a1
147dd625b6021
154028a53d642
hex21a962fc7fd

2313212119037 has 2 divisors, whose sum is σ = 2313212119038. Its totient is φ = 2313212119036.

The previous prime is 2313212119027. The next prime is 2313212119039. The reversal of 2313212119037 is 7309112123132.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1737087096196 + 576125022841 = 1317986^2 + 759029^2 .

It is a cyclic number.

It is not a de Polignac number, because 2313212119037 - 222 = 2313207924733 is a prime.

Together with 2313212119039, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 2313212118988 and 2313212119006.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2313212119039) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1156606059518 + 1156606059519.

It is an arithmetic number, because the mean of its divisors is an integer number (1156606059519).

Almost surely, 22313212119037 is an apocalyptic number.

It is an amenable number.

2313212119037 is a deficient number, since it is larger than the sum of its proper divisors (1).

2313212119037 is an equidigital number, since it uses as much as digits as its factorization.

2313212119037 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13608, while the sum is 35.

The spelling of 2313212119037 in words is "two trillion, three hundred thirteen billion, two hundred twelve million, one hundred nineteen thousand, thirty-seven".