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2313241241041 is a prime number
BaseRepresentation
bin100001101010010111111…
…011000010010111010001
322012010212202111121200001
4201222113323002113101
5300400004224203131
64530404403530001
7326061163056613
oct41522773022721
98163782447601
102313241241041
118120494134a5
123143a3989901
1313a1a372b643
147dd663d6db3
154028cd92261
hex21a97ec25d1

2313241241041 has 2 divisors, whose sum is σ = 2313241241042. Its totient is φ = 2313241241040.

The previous prime is 2313241241039. The next prime is 2313241241071. The reversal of 2313241241041 is 1401421423132.

It is a happy number.

2313241241041 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1255385793600 + 1057855447441 = 1120440^2 + 1028521^2 .

It is a cyclic number.

It is not a de Polignac number, because 2313241241041 - 21 = 2313241241039 is a prime.

Together with 2313241241039, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (2313241241011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1156620620520 + 1156620620521.

It is an arithmetic number, because the mean of its divisors is an integer number (1156620620521).

Almost surely, 22313241241041 is an apocalyptic number.

It is an amenable number.

2313241241041 is a deficient number, since it is larger than the sum of its proper divisors (1).

2313241241041 is an equidigital number, since it uses as much as digits as its factorization.

2313241241041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4608, while the sum is 28.

Adding to 2313241241041 its reverse (1401421423132), we get a palindrome (3714662664173).

The spelling of 2313241241041 in words is "two trillion, three hundred thirteen billion, two hundred forty-one million, two hundred forty-one thousand, forty-one".