Base | Representation |
---|---|
bin | 1010100001010000111111… |
… | …00111111111100111100111 |
3 | 10000220111220012000020211202 |
4 | 11100220133213333213213 |
5 | 11013003320423343101 |
6 | 121111131231353115 |
7 | 4605214603211006 |
oct | 520503747774747 |
9 | 100814805006752 |
10 | 23133224434151 |
11 | 7409822124a57 |
12 | 271745a08279b |
13 | cba5b8a30760 |
14 | 59d922968c3d |
15 | 2a1b3556636b |
hex | 150a1f9ff9e7 |
23133224434151 has 4 divisors (see below), whose sum is σ = 24912703236792. Its totient is φ = 21353745631512.
The previous prime is 23133224434141. The next prime is 23133224434217. The reversal of 23133224434151 is 15143442233132.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 23133224434151 - 230 = 23132150692327 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (23133224434121) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 889739401301 + ... + 889739401326.
It is an arithmetic number, because the mean of its divisors is an integer number (6228175809198).
Almost surely, 223133224434151 is an apocalyptic number.
23133224434151 is a deficient number, since it is larger than the sum of its proper divisors (1779478802641).
23133224434151 is a wasteful number, since it uses less digits than its factorization.
23133224434151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1779478802640.
The product of its digits is 207360, while the sum is 38.
Adding to 23133224434151 its reverse (15143442233132), we get a palindrome (38276666667283).
The spelling of 23133224434151 in words is "twenty-three trillion, one hundred thirty-three billion, two hundred twenty-four million, four hundred thirty-four thousand, one hundred fifty-one".
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