Base | Representation |
---|---|
bin | 110100100110010101101111… |
… | …011011100101011011101111 |
3 | 1010100002020011200212112101122 |
4 | 310212111233123211123233 |
5 | 220310130143334011142 |
6 | 2140000543241131155 |
7 | 66504156642561062 |
oct | 6446255733453357 |
9 | 1110066150775348 |
10 | 231333103032047 |
11 | 677898aa902515 |
12 | 21b41aa4189abb |
13 | 9c10805a07793 |
14 | 411a820b4a8d9 |
15 | 1bb278900e1d2 |
hex | d2656f6e56ef |
231333103032047 has 2 divisors, whose sum is σ = 231333103032048. Its totient is φ = 231333103032046.
The previous prime is 231333103031999. The next prime is 231333103032107. The reversal of 231333103032047 is 740230301333132.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 231333103032047 - 212 = 231333103027951 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 231333103031998 and 231333103032016.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (231333103332047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 115666551516023 + 115666551516024.
It is an arithmetic number, because the mean of its divisors is an integer number (115666551516024).
Almost surely, 2231333103032047 is an apocalyptic number.
231333103032047 is a deficient number, since it is larger than the sum of its proper divisors (1).
231333103032047 is an equidigital number, since it uses as much as digits as its factorization.
231333103032047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 81648, while the sum is 35.
Adding to 231333103032047 its reverse (740230301333132), we get a palindrome (971563404365179).
The spelling of 231333103032047 in words is "two hundred thirty-one trillion, three hundred thirty-three billion, one hundred three million, thirty-two thousand, forty-seven".
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