23133312131 has 2 divisors, whose sum is σ = 23133312132. Its totient is φ = 23133312130.

The previous prime is 23133312119. The next prime is 23133312133. The reversal of 23133312131 is 13121333132.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 23133312131 - 2⁶ = 23133312067 is a prime.

It is a super-2 number, since 2×23133312131² (a number of 22 digits) contains 22 as substring.

Together with 23133312133, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 23133312097 and 23133312106.

It is not a weakly prime, because it can be changed into another prime (23133312133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11566656065 + 11566656066.

It is an arithmetic number, because the mean of its divisors is an integer number (11566656066).

Almost surely, 2^23133312131 is an apocalyptic number.

23133312131 is a deficient number, since it is larger than the sum of its proper divisors (1).

23133312131 is an equidigital number, since it uses as much as digits as its factorization.

23133312131 is an evil number, because the sum of its binary digits is even.

The product of its digits is 972, while the sum is 23.

Adding to 23133312131 its reverse (13121333132), we get a palindrome (36254645263).

The spelling of 23133312131 in words is "twenty-three billion, one hundred thirty-three million, three hundred twelve thousand, one hundred thirty-one".