Base | Representation |
---|---|
bin | 1010100001010001100001… |
… | …11100011111111010111111 |
3 | 10000220112122102210122110020 |
4 | 11100220300330133322333 |
5 | 11013004414321201030 |
6 | 121111220131543223 |
7 | 4605225032156646 |
oct | 520506074377277 |
9 | 100815572718406 |
10 | 23133515022015 |
11 | 740996115aa12 |
12 | 271751b45ab13 |
13 | cba633cb4438 |
14 | 59d94d3ac35d |
15 | 2a1b50d16510 |
hex | 150a30f1febf |
23133515022015 has 128 divisors (see below), whose sum is σ = 41035200970752. Its totient is φ = 11076593909760.
The previous prime is 23133515021999. The next prime is 23133515022017. The reversal of 23133515022015 is 51022051533132.
It is not a de Polignac number, because 23133515022015 - 24 = 23133515021999 is a prime.
It is a super-4 number, since 4×231335150220154 (a number of 55 digits) contains 4444 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (23133515022017) by changing a digit.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 979267494 + ... + 979291116.
It is an arithmetic number, because the mean of its divisors is an integer number (320587507584).
Almost surely, 223133515022015 is an apocalyptic number.
23133515022015 is a deficient number, since it is larger than the sum of its proper divisors (17901685948737).
23133515022015 is a wasteful number, since it uses less digits than its factorization.
23133515022015 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 25449.
The product of its (nonzero) digits is 27000, while the sum is 33.
Adding to 23133515022015 its reverse (51022051533132), we get a palindrome (74155566555147).
The spelling of 23133515022015 in words is "twenty-three trillion, one hundred thirty-three billion, five hundred fifteen million, twenty-two thousand, fifteen".
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