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23134403000425 = 521873494060929
BaseRepresentation
bin1010100001010011001011…
…10111110111100001101001
310000220121221022200121211111
411100221211313313201221
511013013224132003200
6121111444212230321
74605256033646203
oct520514567674151
9100817838617744
1023134403000425
11740a277421272
12271772890b3a1
13cba745c5c052
1459d9d52b9773
152a1ba3c6b0ba
hex150a65df7869

23134403000425 has 12 divisors (see below), whose sum is σ = 28701975667420. Its totient is φ = 18497641144320.

The previous prime is 23134403000363. The next prime is 23134403000431. The reversal of 23134403000425 is 52400030443132.

It is a happy number.

It can be written as a sum of positive squares in 6 ways, for example, as 3079733676889 + 20054669323536 = 1754917^2 + 4478244^2 .

It is not a de Polignac number, because 23134403000425 - 229 = 23133866129513 is a prime.

It is an unprimeable number.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 246983640 + ... + 247077289.

Almost surely, 223134403000425 is an apocalyptic number.

23134403000425 is a gapful number since it is divisible by the number (25) formed by its first and last digit.

It is an amenable number.

23134403000425 is a deficient number, since it is larger than the sum of its proper divisors (5567572666995).

23134403000425 is a wasteful number, since it uses less digits than its factorization.

23134403000425 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 494062812 (or 494062807 counting only the distinct ones).

The product of its (nonzero) digits is 34560, while the sum is 31.

Adding to 23134403000425 its reverse (52400030443132), we get a palindrome (75534433443557).

The spelling of 23134403000425 in words is "twenty-three trillion, one hundred thirty-four billion, four hundred three million, four hundred twenty-five", and thus it is an aban number.

Divisors: 1 5 25 1873 9365 46825 494060929 2470304645 12351523225 925376120017 4626880600085 23134403000425