231413120010251 has 2 divisors, whose sum is σ = 231413120010252. Its totient is φ = 231413120010250.

The previous prime is 231413120010223. The next prime is 231413120010253. The reversal of 231413120010251 is 152010021314132.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-231413120010251 is a prime.

It is a super-3 number, since 3×231413120010251³ (a number of 44 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Sophie Germain prime.

Together with 231413120010253, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 231413120010251.

It is not a weakly prime, because it can be changed into another prime (231413120010253) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 115706560005125 + 115706560005126.

It is an arithmetic number, because the mean of its divisors is an integer number (115706560005126).

Almost surely, 2^{231413120010251} is an apocalyptic number.

231413120010251 is a deficient number, since it is larger than the sum of its proper divisors (1).

231413120010251 is an equidigital number, since it uses as much as digits as its factorization.

231413120010251 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440, while the sum is 26.

Adding to 231413120010251 its reverse (152010021314132), we get a palindrome (383423141324383).

The spelling of 231413120010251 in words is "two hundred thirty-one trillion, four hundred thirteen billion, one hundred twenty million, ten thousand, two hundred fifty-one".