Base | Representation |
---|---|
bin | 1101011110001001001… |
… | …1111000100101101001 |
3 | 211010100202121201110020 |
4 | 3113202103320211221 |
5 | 12242432103130100 |
6 | 254152330511053 |
7 | 22502024435103 |
oct | 3274223704551 |
9 | 733322551406 |
10 | 231430130025 |
11 | 8a170303076 |
12 | 38a29595489 |
13 | 18a92a81c53 |
14 | b2b6442573 |
15 | 60478e55a0 |
hex | 35e24f8969 |
231430130025 has 24 divisors (see below), whose sum is σ = 383937093120. Its totient is φ = 123008130240.
The previous prime is 231430130017. The next prime is 231430130027. The reversal of 231430130025 is 520031034132.
It is not a de Polignac number, because 231430130025 - 23 = 231430130017 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 231430129977 and 231430130004.
It is not an unprimeable number, because it can be changed into a prime (231430130027) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 5243785 + ... + 5287734.
It is an arithmetic number, because the mean of its divisors is an integer number (15997378880).
Almost surely, 2231430130025 is an apocalyptic number.
231430130025 is a gapful number since it is divisible by the number (25) formed by its first and last digit.
It is an amenable number.
231430130025 is a deficient number, since it is larger than the sum of its proper divisors (152506963095).
231430130025 is a wasteful number, since it uses less digits than its factorization.
231430130025 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10531825 (or 10531820 counting only the distinct ones).
The product of its (nonzero) digits is 2160, while the sum is 24.
Adding to 231430130025 its reverse (520031034132), we get a palindrome (751461164157).
The spelling of 231430130025 in words is "two hundred thirty-one billion, four hundred thirty million, one hundred thirty thousand, twenty-five".
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