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231440044133 = 297980691177
BaseRepresentation
bin1101011110001011100…
…1101101000001100101
3211010101110021102001102
43113202321231001211
512242442122403013
6254153323205445
722502204626154
oct3274271550145
9733343242042
10231440044133
118a175964751
1238a30976885
1318a94b4369c
14b2b78a359b
156048702d58
hex35e2e6d065

231440044133 has 4 divisors (see below), whose sum is σ = 239420735340. Its totient is φ = 223459352928.

The previous prime is 231440044111. The next prime is 231440044151. The reversal of 231440044133 is 331440044132.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 76064536804 + 155375507329 = 275798^2 + 394177^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-231440044133 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (29), and also a Moran number because the ratio is a prime number: 7980691177 = 231440044133 / (2 + 3 + 1 + 4 + 4 + 0 + 0 + 4 + 4 + 1 + 3 + 3).

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 231440044096 and 231440044105.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (231440044153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3990345560 + ... + 3990345617.

It is an arithmetic number, because the mean of its divisors is an integer number (59855183835).

Almost surely, 2231440044133 is an apocalyptic number.

It is an amenable number.

231440044133 is a deficient number, since it is larger than the sum of its proper divisors (7980691207).

231440044133 is an equidigital number, since it uses as much as digits as its factorization.

231440044133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7980691206.

The product of its (nonzero) digits is 13824, while the sum is 29.

Adding to 231440044133 its reverse (331440044132), we get a palindrome (562880088265).

Subtracting 231440044133 from its reverse (331440044132), we obtain a palindrome (99999999999).

The spelling of 231440044133 in words is "two hundred thirty-one billion, four hundred forty million, forty-four thousand, one hundred thirty-three".

Divisors: 1 29 7980691177 231440044133