Base | Representation |
---|---|
bin | 1010100001100111100000… |
… | …00000000100100110101111 |
3 | 10000221200002110202221222202 |
4 | 11100303300000010212233 |
5 | 11013203043421412201 |
6 | 121120450410332115 |
7 | 4606123236553436 |
oct | 520636000044657 |
9 | 100850073687882 |
10 | 23145310341551 |
11 | 7413964322082 |
12 | 271987172a03b |
13 | cbb793913458 |
14 | 5a034bb4a11d |
15 | 2a20e1605c6b |
hex | 150cf00049af |
23145310341551 has 64 divisors (see below), whose sum is σ = 24852417408000. Its totient is φ = 21509886182400.
The previous prime is 23145310341539. The next prime is 23145310341583. The reversal of 23145310341551 is 15514301354132.
It is a cyclic number.
It is not a de Polignac number, because 23145310341551 - 218 = 23145310079407 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (23145310341511) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 11648368580 + ... + 11648370566.
It is an arithmetic number, because the mean of its divisors is an integer number (388319022000).
Almost surely, 223145310341551 is an apocalyptic number.
23145310341551 is a deficient number, since it is larger than the sum of its proper divisors (1707107066449).
23145310341551 is a wasteful number, since it uses less digits than its factorization.
23145310341551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2640.
The product of its (nonzero) digits is 108000, while the sum is 38.
Adding to 23145310341551 its reverse (15514301354132), we get a palindrome (38659611695683).
The spelling of 23145310341551 in words is "twenty-three trillion, one hundred forty-five billion, three hundred ten million, three hundred forty-one thousand, five hundred fifty-one".
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