Base | Representation |
---|---|
bin | 10101100100000110… |
… | …000000000100000111 |
3 | 2012202122120201212002 |
4 | 111210012000010013 |
5 | 334404424144312 |
6 | 14345321215515 |
7 | 1446531603464 |
oct | 254406000407 |
9 | 65678521762 |
10 | 23154131207 |
11 | 99019a3529 |
12 | 45a233159b |
13 | 224cca656c |
14 | 119917066b |
15 | 907b084c2 |
hex | 564180107 |
23154131207 has 2 divisors, whose sum is σ = 23154131208. Its totient is φ = 23154131206.
The previous prime is 23154131197. The next prime is 23154131213. The reversal of 23154131207 is 70213145132.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 23154131207 - 24 = 23154131191 is a prime.
It is a super-2 number, since 2×231541312072 (a number of 22 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 23154131207.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (23154131107) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11577065603 + 11577065604.
It is an arithmetic number, because the mean of its divisors is an integer number (11577065604).
Almost surely, 223154131207 is an apocalyptic number.
23154131207 is a deficient number, since it is larger than the sum of its proper divisors (1).
23154131207 is an equidigital number, since it uses as much as digits as its factorization.
23154131207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5040, while the sum is 29.
Adding to 23154131207 its reverse (70213145132), we get a palindrome (93367276339).
The spelling of 23154131207 in words is "twenty-three billion, one hundred fifty-four million, one hundred thirty-one thousand, two hundred seven".
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