Base | Representation |
---|---|
bin | 10101100110000101… |
… | …011101100000110101 |
3 | 2012211222110021202021 |
4 | 111212011131200311 |
5 | 334442002402432 |
6 | 14352513313141 |
7 | 1450415605303 |
oct | 254605354065 |
9 | 65758407667 |
10 | 23187544117 |
11 | 9919845101 |
12 | 45b15657b1 |
13 | 2256ba4b0a |
14 | 119d78b273 |
15 | 90aa08697 |
hex | 56615d835 |
23187544117 has 2 divisors, whose sum is σ = 23187544118. Its totient is φ = 23187544116.
The previous prime is 23187544103. The next prime is 23187544129. The reversal of 23187544117 is 71144578132.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 22439740401 + 747803716 = 149799^2 + 27346^2 .
It is a cyclic number.
It is not a de Polignac number, because 23187544117 - 27 = 23187543989 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (23187544147) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11593772058 + 11593772059.
It is an arithmetic number, because the mean of its divisors is an integer number (11593772059).
Almost surely, 223187544117 is an apocalyptic number.
It is an amenable number.
23187544117 is a deficient number, since it is larger than the sum of its proper divisors (1).
23187544117 is an equidigital number, since it uses as much as digits as its factorization.
23187544117 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 188160, while the sum is 43.
The spelling of 23187544117 in words is "twenty-three billion, one hundred eighty-seven million, five hundred forty-four thousand, one hundred seventeen".
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