Base | Representation |
---|---|
bin | 1101100000010001011… |
… | …0000000100000110001 |
3 | 211011211120000121121222 |
4 | 3120010112000200301 |
5 | 12300114241041423 |
6 | 254325124554425 |
7 | 22522126625651 |
oct | 3300426004061 |
9 | 734746017558 |
10 | 232001112113 |
11 | 8a4336413a1 |
12 | 38b68852a15 |
13 | 18b5415a884 |
14 | b32c1d4361 |
15 | 607cad03c8 |
hex | 3604580831 |
232001112113 has 2 divisors, whose sum is σ = 232001112114. Its totient is φ = 232001112112.
The previous prime is 232001112073. The next prime is 232001112139. The reversal of 232001112113 is 311211100232.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 156410758144 + 75590353969 = 395488^2 + 274937^2 .
It is a cyclic number.
It is not a de Polignac number, because 232001112113 - 222 = 231996917809 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 232001112091 and 232001112100.
It is not a weakly prime, because it can be changed into another prime (232001112163) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 116000556056 + 116000556057.
It is an arithmetic number, because the mean of its divisors is an integer number (116000556057).
Almost surely, 2232001112113 is an apocalyptic number.
It is an amenable number.
232001112113 is a deficient number, since it is larger than the sum of its proper divisors (1).
232001112113 is an equidigital number, since it uses as much as digits as its factorization.
232001112113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 232001112113 its reverse (311211100232), we get a palindrome (543212212345).
The spelling of 232001112113 in words is "two hundred thirty-two billion, one million, one hundred twelve thousand, one hundred thirteen".
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