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23201102013 = 320393792889
BaseRepresentation
bin10101100110111001…
…001011100010111101
32012212220222002200120
4111212321023202331
5340003440231023
614354120045153
71450642053555
oct254671134275
965786862616
1023201102013
119926465381
1245b60037b9
132259940c3b
1411a14ba165
1590bcd58e3
hex566e4b8bd

23201102013 has 8 divisors (see below), whose sum is σ = 30949982400. Its totient is φ = 15459811488.

The previous prime is 23201102009. The next prime is 23201102021. The reversal of 23201102013 is 31020110232.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 23201102013 - 22 = 23201102009 is a prime.

It is a super-2 number, since 2×232011020132 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 23201101983 and 23201102001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (23201102083) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1890328 + ... + 1902561.

It is an arithmetic number, because the mean of its divisors is an integer number (3868747800).

Almost surely, 223201102013 is an apocalyptic number.

It is an amenable number.

23201102013 is a deficient number, since it is larger than the sum of its proper divisors (7748880387).

23201102013 is a wasteful number, since it uses less digits than its factorization.

23201102013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3794931.

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 23201102013 its reverse (31020110232), we get a palindrome (54221212245).

The spelling of 23201102013 in words is "twenty-three billion, two hundred one million, one hundred two thousand, thirteen".

Divisors: 1 3 2039 6117 3792889 11378667 7733700671 23201102013