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2320131301381 is a prime number
BaseRepresentation
bin100001110000110010100…
…110100010000000000101
322012210122221100221121001
4201300302212202000011
5301003112103121011
64533504213453301
7326424005445235
oct41606246420005
98183587327531
102320131301381
11814a646a7843
123157a7341231
1313aa3102081a
148041b4d5cc5
1540542be17c1
hex21c329a2005

2320131301381 has 2 divisors, whose sum is σ = 2320131301382. Its totient is φ = 2320131301380.

The previous prime is 2320131301373. The next prime is 2320131301409. The reversal of 2320131301381 is 1831031310232.

It is an a-pointer prime, because the next prime (2320131301409) can be obtained adding 2320131301381 to its sum of digits (28).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1977243761025 + 342887540356 = 1406145^2 + 585566^2 .

It is a cyclic number.

It is not a de Polignac number, because 2320131301381 - 23 = 2320131301373 is a prime.

It is a super-2 number, since 2×23201313013812 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2320131331381) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1160065650690 + 1160065650691.

It is an arithmetic number, because the mean of its divisors is an integer number (1160065650691).

Almost surely, 22320131301381 is an apocalyptic number.

It is an amenable number.

2320131301381 is a deficient number, since it is larger than the sum of its proper divisors (1).

2320131301381 is an equidigital number, since it uses as much as digits as its factorization.

2320131301381 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2592, while the sum is 28.

The spelling of 2320131301381 in words is "two trillion, three hundred twenty billion, one hundred thirty-one million, three hundred one thousand, three hundred eighty-one".