Base | Representation |
---|---|
bin | 10101100111100011… |
… | …001011000100100001 |
3 | 2012220200200100221222 |
4 | 111213203023010201 |
5 | 340014300010423 |
6 | 14355152024425 |
7 | 1451134452263 |
oct | 254743130441 |
9 | 65820610858 |
10 | 23212110113 |
11 | 99316a3985 |
12 | 45b9832115 |
13 | 225bcc65ca |
14 | 11a2b43b33 |
15 | 90cc5c3c8 |
hex | 5678cb121 |
23212110113 has 2 divisors, whose sum is σ = 23212110114. Its totient is φ = 23212110112.
The previous prime is 23212110109. The next prime is 23212110127. The reversal of 23212110113 is 31101121232.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 19800148369 + 3411961744 = 140713^2 + 58412^2 .
It is a cyclic number.
It is not a de Polignac number, because 23212110113 - 22 = 23212110109 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 23212110091 and 23212110100.
It is not a weakly prime, because it can be changed into another prime (23212110013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11606055056 + 11606055057.
It is an arithmetic number, because the mean of its divisors is an integer number (11606055057).
Almost surely, 223212110113 is an apocalyptic number.
It is an amenable number.
23212110113 is a deficient number, since it is larger than the sum of its proper divisors (1).
23212110113 is an equidigital number, since it uses as much as digits as its factorization.
23212110113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 23212110113 its reverse (31101121232), we get a palindrome (54313231345).
The spelling of 23212110113 in words is "twenty-three billion, two hundred twelve million, one hundred ten thousand, one hundred thirteen".
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