Base | Representation |
---|---|
bin | 100001110100110001110… |
… | …101001101100110001001 |
3 | 22020012201100210001100111 |
4 | 201310301311031212021 |
5 | 301040344303340131 |
6 | 4535453140434321 |
7 | 326635062253042 |
oct | 41646165154611 |
9 | 8205640701314 |
10 | 2324413340041 |
11 | 816861807871 |
12 | 3165a13a89a1 |
13 | 13b2641c1800 |
14 | 807060a58c9 |
15 | 406e3ac8ab1 |
hex | 21d31d4d989 |
2324413340041 has 96 divisors (see below), whose sum is σ = 2861134036992. Its totient is φ = 1876362808320.
The previous prime is 2324413340027. The next prime is 2324413340057. The reversal of 2324413340041 is 1400433144232.
It is not a de Polignac number, because 2324413340041 - 29 = 2324413339529 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2324413339985 and 2324413340012.
It is not an unprimeable number, because it can be changed into a prime (2324413340141) by changing a digit.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 542704686 + ... + 542708968.
It is an arithmetic number, because the mean of its divisors is an integer number (29803479552).
Almost surely, 22324413340041 is an apocalyptic number.
It is an amenable number.
2324413340041 is a deficient number, since it is larger than the sum of its proper divisors (536720696951).
2324413340041 is a wasteful number, since it uses less digits than its factorization.
2324413340041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4583 (or 4570 counting only the distinct ones).
The product of its (nonzero) digits is 27648, while the sum is 31.
Adding to 2324413340041 its reverse (1400433144232), we get a palindrome (3724846484273).
The spelling of 2324413340041 in words is "two trillion, three hundred twenty-four billion, four hundred thirteen million, three hundred forty thousand, forty-one".
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