Base | Representation |
---|---|
bin | 1010100100100000001000… |
… | …01100001100011001001111 |
3 | 10001022010221112010112220222 |
4 | 11102100010030030121033 |
5 | 11021314044411430221 |
6 | 121234202323501555 |
7 | 4616232504111452 |
oct | 522200414143117 |
9 | 101263845115828 |
10 | 23244433311311 |
11 | 74519aa6943a3 |
12 | 2734b158278bb |
13 | cc7c2c80c594 |
14 | 5a507250d499 |
15 | 2a499384e9ab |
hex | 15240430c64f |
23244433311311 has 2 divisors, whose sum is σ = 23244433311312. Its totient is φ = 23244433311310.
The previous prime is 23244433311277. The next prime is 23244433311331. The reversal of 23244433311311 is 11311333444232.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-23244433311311 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (23244433311331) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11622216655655 + 11622216655656.
It is an arithmetic number, because the mean of its divisors is an integer number (11622216655656).
Almost surely, 223244433311311 is an apocalyptic number.
23244433311311 is a deficient number, since it is larger than the sum of its proper divisors (1).
23244433311311 is an equidigital number, since it uses as much as digits as its factorization.
23244433311311 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 62208, while the sum is 35.
Adding to 23244433311311 its reverse (11311333444232), we get a palindrome (34555766755543).
The spelling of 23244433311311 in words is "twenty-three trillion, two hundred forty-four billion, four hundred thirty-three million, three hundred eleven thousand, three hundred eleven".
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