23300040113 has 4 divisors (see below), whose sum is σ = 26628617280. Its totient is φ = 19971462948.

The previous prime is 23300040089. The next prime is 23300040139. The reversal of 23300040113 is 31104000332.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 23300040113 - 2⁸ = 23300039857 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 23300040091 and 23300040100.

It is not an unprimeable number, because it can be changed into a prime (23300040173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1664288573 + ... + 1664288586.

It is an arithmetic number, because the mean of its divisors is an integer number (6657154320).

Almost surely, 2^23300040113 is an apocalyptic number.

It is an amenable number.

23300040113 is a deficient number, since it is larger than the sum of its proper divisors (3328577167).

23300040113 is an equidigital number, since it uses as much as digits as its factorization.

23300040113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3328577166.

The product of its (nonzero) digits is 216, while the sum is 17.

Adding to 23300040113 its reverse (31104000332), we get a palindrome (54404040445).

The spelling of 23300040113 in words is "twenty-three billion, three hundred million, forty thousand, one hundred thirteen".