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2330033341121 is a prime number
BaseRepresentation
bin100001111010000000110…
…011110100001011000001
322020202020000210200111122
4201322000303310023001
5301133402013403441
64542222540522025
7330224253421613
oct41720063641301
98222200720448
102330033341121
11819186093862
123176ab550315
1313b94b62ca35
1480aba638db3
154092219e34b
hex21e80cf42c1

2330033341121 has 2 divisors, whose sum is σ = 2330033341122. Its totient is φ = 2330033341120.

The previous prime is 2330033341061. The next prime is 2330033341123. The reversal of 2330033341121 is 1211433300332.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1892234092225 + 437799248896 = 1375585^2 + 661664^2 .

It is a cyclic number.

It is not a de Polignac number, because 2330033341121 - 26 = 2330033341057 is a prime.

Together with 2330033341123, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (2330033341123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1165016670560 + 1165016670561.

It is an arithmetic number, because the mean of its divisors is an integer number (1165016670561).

Almost surely, 22330033341121 is an apocalyptic number.

It is an amenable number.

2330033341121 is a deficient number, since it is larger than the sum of its proper divisors (1).

2330033341121 is an equidigital number, since it uses as much as digits as its factorization.

2330033341121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3888, while the sum is 26.

Adding to 2330033341121 its reverse (1211433300332), we get a palindrome (3541466641453).

The spelling of 2330033341121 in words is "two trillion, three hundred thirty billion, thirty-three million, three hundred forty-one thousand, one hundred twenty-one".