Base | Representation |
---|---|
bin | 1101100100101111100… |
… | …0011100000100010101 |
3 | 211021221012102111121211 |
4 | 3121023320130010111 |
5 | 12310044014221323 |
6 | 255044201341421 |
7 | 22563642341641 |
oct | 3311370340425 |
9 | 737835374554 |
10 | 233201320213 |
11 | 8a99a07a514 |
12 | 39242797871 |
13 | 18cb59c5994 |
14 | b403779c21 |
15 | 60ed15c70d |
hex | 364be1c115 |
233201320213 has 2 divisors, whose sum is σ = 233201320214. Its totient is φ = 233201320212.
The previous prime is 233201320211. The next prime is 233201320249. The reversal of 233201320213 is 312023102332.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 229975875364 + 3225444849 = 479558^2 + 56793^2 .
It is a cyclic number.
It is not a de Polignac number, because 233201320213 - 21 = 233201320211 is a prime.
Together with 233201320211, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (233201320211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 116600660106 + 116600660107.
It is an arithmetic number, because the mean of its divisors is an integer number (116600660107).
Almost surely, 2233201320213 is an apocalyptic number.
It is an amenable number.
233201320213 is a deficient number, since it is larger than the sum of its proper divisors (1).
233201320213 is an equidigital number, since it uses as much as digits as its factorization.
233201320213 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 22.
Adding to 233201320213 its reverse (312023102332), we get a palindrome (545224422545).
The spelling of 233201320213 in words is "two hundred thirty-three billion, two hundred one million, three hundred twenty thousand, two hundred thirteen".
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