Base | Representation |
---|---|
bin | 1010100111100101110001… |
… | …01010110001011010100111 |
3 | 10001200021211022102020111121 |
4 | 11103302320222301122213 |
5 | 11030033401323110010 |
6 | 121355031251514411 |
7 | 4630010105614516 |
oct | 523627052613247 |
9 | 101607738366447 |
10 | 23350540441255 |
11 | 74929aa371625 |
12 | 27515a88b8a07 |
13 | 1004c3c656981 |
14 | 5aa25a6a867d |
15 | 2a7603cd43da |
hex | 153cb8ab16a7 |
23350540441255 has 4 divisors (see below), whose sum is σ = 28020648529512. Its totient is φ = 18680432353000.
The previous prime is 23350540441231. The next prime is 23350540441289. The reversal of 23350540441255 is 55214404505332.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 23350540441255 - 225 = 23350506886823 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2335054044121 + ... + 2335054044130.
It is an arithmetic number, because the mean of its divisors is an integer number (7005162132378).
Almost surely, 223350540441255 is an apocalyptic number.
23350540441255 is a deficient number, since it is larger than the sum of its proper divisors (4670108088257).
23350540441255 is an equidigital number, since it uses as much as digits as its factorization.
23350540441255 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4670108088256.
The product of its (nonzero) digits is 1440000, while the sum is 43.
Adding to 23350540441255 its reverse (55214404505332), we get a palindrome (78564944946587).
The spelling of 23350540441255 in words is "twenty-three trillion, three hundred fifty billion, five hundred forty million, four hundred forty-one thousand, two hundred fifty-five".
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