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2340100331311 = 10121094214999
BaseRepresentation
bin100010000011011000110…
…110010101011100101111
322021201012121121202220011
4202003120312111130233
5301320011141100221
64551005515234051
7331031603423341
oct42033066253457
98251177552804
102340100331311
118224816a3566
1231963aa48927
1313c894173a72
1481393639291
1540d10d911e1
hex220d8d9572f

2340100331311 has 24 divisors (see below), whose sum is σ = 2391326300000. Its totient is φ = 2289763728000.

The previous prime is 2340100331281. The next prime is 2340100331329. The reversal of 2340100331311 is 1131330010432.

2340100331311 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 2340100331311 - 235 = 2305740592943 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2340100331351) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 468111190 + ... + 468116188.

Almost surely, 22340100331311 is an apocalyptic number.

2340100331311 is a deficient number, since it is larger than the sum of its proper divisors (51225968689).

2340100331311 is a wasteful number, since it uses less digits than its factorization.

2340100331311 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5731 (or 5630 counting only the distinct ones).

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 2340100331311 its reverse (1131330010432), we get a palindrome (3471430341743).

The spelling of 2340100331311 in words is "two trillion, three hundred forty billion, one hundred million, three hundred thirty-one thousand, three hundred eleven".

Divisors: 1 101 109 421 4999 10201 11009 42521 45889 504899 544891 1111909 2104579 4294621 4634789 50994799 55033991 212562479 229399111 468113689 5558433091 21468810379 23169310211 2340100331311