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234011013132 = 223131500070597
BaseRepresentation
bin1101100111110000100…
…1001011000000001100
3211101000122000011111110
43121330021023000030
512313223304410012
6255300404052020
722623003535461
oct3317411130014
9741018004443
10234011013132
1190275130816
1239429994010
13190b4690710
14b47d109668
15614929b73c
hex367c24b00c

234011013132 has 24 divisors (see below), whose sum is σ = 588027674416. Its totient is φ = 72003388608.

The previous prime is 234011013113. The next prime is 234011013133. The reversal of 234011013132 is 231310110432.

It is a super-2 number, since 2×2340110131322 (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 234011013099 and 234011013108.

It is not an unprimeable number, because it can be changed into a prime (234011013133) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 750035143 + ... + 750035454.

Almost surely, 2234011013132 is an apocalyptic number.

It is an amenable number.

234011013132 is an abundant number, since it is smaller than the sum of its proper divisors (354016661284).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

234011013132 is a wasteful number, since it uses less digits than its factorization.

234011013132 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1500070617 (or 1500070615 counting only the distinct ones).

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 234011013132 its reverse (231310110432), we get a palindrome (465321123564).

The spelling of 234011013132 in words is "two hundred thirty-four billion, eleven million, thirteen thousand, one hundred thirty-two".

Divisors: 1 2 3 4 6 12 13 26 39 52 78 156 1500070597 3000141194 4500211791 6000282388 9000423582 18000847164 19500917761 39001835522 58502753283 78003671044 117005506566 234011013132