23403000011 has 2 divisors, whose sum is σ = 23403000012. Its totient is φ = 23403000010.

The previous prime is 23402999999. The next prime is 23403000013. The reversal of 23403000011 is 11000030432.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 23403000011 - 2⁶ = 23402999947 is a prime.

Together with 23403000013, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 23403000011.

It is not a weakly prime, because it can be changed into another prime (23403000013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11701500005 + 11701500006.

It is an arithmetic number, because the mean of its divisors is an integer number (11701500006).

Almost surely, 2^23403000011 is an apocalyptic number.

23403000011 is a deficient number, since it is larger than the sum of its proper divisors (1).

23403000011 is an equidigital number, since it uses as much as digits as its factorization.

23403000011 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 14.

Adding to 23403000011 its reverse (11000030432), we get a palindrome (34403030443).

The spelling of 23403000011 in words is "twenty-three billion, four hundred three million, eleven", and thus it is an aban number.