Base | Representation |
---|---|
bin | 10101110011000000… |
… | …000100010101111111 |
3 | 2020102002012021112121 |
4 | 111303000010111333 |
5 | 340412440442421 |
6 | 14430213543411 |
7 | 1455656464456 |
oct | 256300042577 |
9 | 66362167477 |
10 | 23404234111 |
11 | 9a20097545 |
12 | 4652044b67 |
13 | 228ca53a4b |
14 | 11c0475b9d |
15 | 91ea5cd41 |
hex | 57300457f |
23404234111 has 4 divisors (see below), whose sum is σ = 23454350712. Its totient is φ = 23354117512.
The previous prime is 23404234103. The next prime is 23404234121. The reversal of 23404234111 is 11143240432.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 23404234111 - 23 = 23404234103 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (23404234121) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25057600 + ... + 25058533.
It is an arithmetic number, because the mean of its divisors is an integer number (5863587678).
Almost surely, 223404234111 is an apocalyptic number.
23404234111 is a deficient number, since it is larger than the sum of its proper divisors (50116601).
23404234111 is an equidigital number, since it uses as much as digits as its factorization.
23404234111 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 50116600.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 23404234111 its reverse (11143240432), we get a palindrome (34547474543).
The spelling of 23404234111 in words is "twenty-three billion, four hundred four million, two hundred thirty-four thousand, one hundred eleven".
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