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23433105011 is a prime number
BaseRepresentation
bin10101110100101110…
…001100111001110011
32020111002112001222012
4111310232030321303
5340442333330021
614433124433135
71456460051261
oct256456147163
966432461865
1023433105011
119a35416698
12465b8487ab
132295a21b14
1411c422d431
1592236235b
hex574b8ce73

23433105011 has 2 divisors, whose sum is σ = 23433105012. Its totient is φ = 23433105010.

The previous prime is 23433104999. The next prime is 23433105013. The reversal of 23433105011 is 11050133432.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-23433105011 is a prime.

It is a super-2 number, since 2×234331050112 (a number of 22 digits) contains 22 as substring.

Together with 23433105013, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (23433105013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11716552505 + 11716552506.

It is an arithmetic number, because the mean of its divisors is an integer number (11716552506).

Almost surely, 223433105011 is an apocalyptic number.

23433105011 is a deficient number, since it is larger than the sum of its proper divisors (1).

23433105011 is an equidigital number, since it uses as much as digits as its factorization.

23433105011 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1080, while the sum is 23.

Adding to 23433105011 its reverse (11050133432), we get a palindrome (34483238443).

The spelling of 23433105011 in words is "twenty-three billion, four hundred thirty-three million, one hundred five thousand, eleven".