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234411421201303 is a prime number
BaseRepresentation
bin110101010011001000101001…
…011111011111001110010111
31010201222111211222121000210011
4311103020221133133032113
5221211044042311420203
62150315041550541051
7100242444353360143
oct6523105137371627
91121874758530704
10234411421201303
11687663641a1a05
122235a606807787
13a0a4b960b4c68
1441c58052a6223
151c178a425b76d
hexd532297df397

234411421201303 has 2 divisors, whose sum is σ = 234411421201304. Its totient is φ = 234411421201302.

The previous prime is 234411421201253. The next prime is 234411421201367. The reversal of 234411421201303 is 303102124114432.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 234411421201303 - 233 = 234402831266711 is a prime.

It is a super-2 number, since 2×2344114212013032 (a number of 30 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (234411421201703) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 117205710600651 + 117205710600652.

It is an arithmetic number, because the mean of its divisors is an integer number (117205710600652).

Almost surely, 2234411421201303 is an apocalyptic number.

234411421201303 is a deficient number, since it is larger than the sum of its proper divisors (1).

234411421201303 is an equidigital number, since it uses as much as digits as its factorization.

234411421201303 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 234411421201303 its reverse (303102124114432), we get a palindrome (537513545315735).

The spelling of 234411421201303 in words is "two hundred thirty-four trillion, four hundred eleven billion, four hundred twenty-one million, two hundred one thousand, three hundred three".