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2344114433 = 10921505637
BaseRepresentation
bin1000101110111000…
…0101100100000001
320001100212100111002
42023232011210001
514300043130213
61024334301345
7112042433603
oct21356054401
96040770432
102344114433
11aa3211961
12555057855
132b484c67b
14183473173
15dabd7658
hex8bb85901

2344114433 has 4 divisors (see below), whose sum is σ = 2365620180. Its totient is φ = 2322608688.

The previous prime is 2344114429. The next prime is 2344114453. The reversal of 2344114433 is 3344114432.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1202147584 + 1141966849 = 34672^2 + 33793^2 .

It is a cyclic number.

It is not a de Polignac number, because 2344114433 - 22 = 2344114429 is a prime.

It is a super-2 number, since 2×23441144332 = 10989744949997822978, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2344114396 and 2344114405.

It is not an unprimeable number, because it can be changed into a prime (2344114453) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10752710 + ... + 10752927.

It is an arithmetic number, because the mean of its divisors is an integer number (591405045).

Almost surely, 22344114433 is an apocalyptic number.

It is an amenable number.

2344114433 is a deficient number, since it is larger than the sum of its proper divisors (21505747).

2344114433 is a wasteful number, since it uses less digits than its factorization.

2344114433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 21505746.

The product of its digits is 13824, while the sum is 29.

The square root of 2344114433 is about 48416.0555291321. The cubic root of 2344114433 is about 1328.3920555280.

Adding to 2344114433 its reverse (3344114432), we get a palindrome (5688228865).

Subtracting 2344114433 from its reverse (3344114432), we obtain a palindrome (999999999).

The spelling of 2344114433 in words is "two billion, three hundred forty-four million, one hundred fourteen thousand, four hundred thirty-three".

Divisors: 1 109 21505637 2344114433