Search a number
-
+
234971141 is a prime number
BaseRepresentation
bin11100000000101…
…10000000000101
3121101010202210212
432000112000011
5440123034031
635152125205
75552136026
oct1600260005
9541122725
10234971141
111106a9329
1266836805
13398acba2
14232c6c4d
151596612b
hexe016005

234971141 has 2 divisors, whose sum is σ = 234971142. Its totient is φ = 234971140.

The previous prime is 234971117. The next prime is 234971173. The reversal of 234971141 is 141179432.

It is an a-pointer prime, because the next prime (234971173) can be obtained adding 234971141 to its sum of digits (32).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 139830625 + 95140516 = 11825^2 + 9754^2 .

It is a cyclic number.

It is not a de Polignac number, because 234971141 - 214 = 234954757 is a prime.

It is a super-2 number, since 2×2349711412 = 110422874205683762, which contains 22 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 234971098 and 234971107.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (234971441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 117485570 + 117485571.

It is an arithmetic number, because the mean of its divisors is an integer number (117485571).

Almost surely, 2234971141 is an apocalyptic number.

It is an amenable number.

234971141 is a deficient number, since it is larger than the sum of its proper divisors (1).

234971141 is an equidigital number, since it uses as much as digits as its factorization.

234971141 is an evil number, because the sum of its binary digits is even.

The product of its digits is 6048, while the sum is 32.

The square root of 234971141 is about 15328.7684110629. The cubic root of 234971141 is about 617.0753173845.

The spelling of 234971141 in words is "two hundred thirty-four million, nine hundred seventy-one thousand, one hundred forty-one".