240024114131 has 2 divisors, whose sum is σ = 240024114132. Its totient is φ = 240024114130.

The previous prime is 240024114107. The next prime is 240024114133. The reversal of 240024114131 is 131411420042.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 240024114131 - 2¹⁸ = 240023851987 is a prime.

It is a super-2 number, since 2×240024114131² (a number of 24 digits) contains 22 as substring.

Together with 240024114133, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 240024114097 and 240024114106.

It is not a weakly prime, because it can be changed into another prime (240024114133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 120012057065 + 120012057066.

It is an arithmetic number, because the mean of its divisors is an integer number (120012057066).

Almost surely, 2^240024114131 is an apocalyptic number.

240024114131 is a deficient number, since it is larger than the sum of its proper divisors (1).

240024114131 is an equidigital number, since it uses as much as digits as its factorization.

240024114131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 240024114131 its reverse (131411420042), we get a palindrome (371435534173).

The spelling of 240024114131 in words is "two hundred forty billion, twenty-four million, one hundred fourteen thousand, one hundred thirty-one".