Base | Representation |
---|---|
bin | 100010111110111010011… |
… | …010110100110001000001 |
3 | 22111211011220001102111010 |
4 | 202332322122310301001 |
5 | 303341410131000023 |
6 | 5040220001511133 |
7 | 335453500333062 |
oct | 42767232646101 |
9 | 8454156042433 |
10 | 2404014312513 |
11 | 84759a452630 |
12 | 329ab76424a9 |
13 | 14590b765858 |
14 | 844d7c50569 |
15 | 42802027093 |
hex | 22fba6b4c41 |
2404014312513 has 8 divisors (see below), whose sum is σ = 3496748090976. Its totient is φ = 1456978371200.
The previous prime is 2404014312493. The next prime is 2404014312551. The reversal of 2404014312513 is 3152134104042.
2404014312513 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 2404014312513 - 25 = 2404014312481 is a prime.
It is not an unprimeable number, because it can be changed into a prime (2404014312613) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 36424459248 + ... + 36424459313.
It is an arithmetic number, because the mean of its divisors is an integer number (437093511372).
Almost surely, 22404014312513 is an apocalyptic number.
It is an amenable number.
2404014312513 is a deficient number, since it is larger than the sum of its proper divisors (1092733778463).
2404014312513 is a wasteful number, since it uses less digits than its factorization.
2404014312513 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 72848918575.
The product of its (nonzero) digits is 11520, while the sum is 30.
Adding to 2404014312513 its reverse (3152134104042), we get a palindrome (5556148416555).
The spelling of 2404014312513 in words is "two trillion, four hundred four billion, fourteen million, three hundred twelve thousand, five hundred thirteen".
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