Base | Representation |
---|---|
bin | 100011000110100000101… |
… | …010010101001010010111 |
3 | 22112121020102101012002021 |
4 | 203012200222111022113 |
5 | 304010112024314333 |
6 | 5044045255354011 |
7 | 336162605404531 |
oct | 43064052251227 |
9 | 8477212335067 |
10 | 2412172104343 |
11 | 84aaa62a4351 |
12 | 32b5b3682907 |
13 | 14660b8a5301 |
14 | 84a6d470851 |
15 | 42b2d2e082d |
hex | 231a0a95297 |
2412172104343 has 2 divisors, whose sum is σ = 2412172104344. Its totient is φ = 2412172104342.
The previous prime is 2412172104217. The next prime is 2412172104373. The reversal of 2412172104343 is 3434012712142.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2412172104343 - 213 = 2412172096151 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2412172104299 and 2412172104308.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2412172104373) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1206086052171 + 1206086052172.
It is an arithmetic number, because the mean of its divisors is an integer number (1206086052172).
Almost surely, 22412172104343 is an apocalyptic number.
2412172104343 is a deficient number, since it is larger than the sum of its proper divisors (1).
2412172104343 is an equidigital number, since it uses as much as digits as its factorization.
2412172104343 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 32256, while the sum is 34.
Adding to 2412172104343 its reverse (3434012712142), we get a palindrome (5846184816485).
The spelling of 2412172104343 in words is "two trillion, four hundred twelve billion, one hundred seventy-two million, one hundred four thousand, three hundred forty-three".
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