Base | Representation |
---|---|
bin | 110110110110001110000010… |
… | …001110100100110100010001 |
3 | 1011122002110002201202102022100 |
4 | 312312032002032210310101 |
5 | 223104123421333313040 |
6 | 2213011045342431013 |
7 | 101544413126530515 |
oct | 6666160216446421 |
9 | 1148073081672270 |
10 | 241220433104145 |
11 | 6a95101397a040 |
12 | 2307a176b92469 |
13 | a479cb247b3c1 |
14 | 437d1ba250145 |
15 | 1cd4a6c764b30 |
hex | db63823a4d11 |
241220433104145 has 48 divisors (see below), whose sum is σ = 456848772441984. Its totient is φ = 116770012128000.
The previous prime is 241220433104137. The next prime is 241220433104159. The reversal of 241220433104145 is 541401334022142.
241220433104145 is a `hidden beast` number, since 2 + 4 + 1 + 2 + 204 + 3 + 31 + 0 + 414 + 5 = 666.
It is not a de Polignac number, because 241220433104145 - 23 = 241220433104137 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 385831876 + ... + 386456565.
It is an arithmetic number, because the mean of its divisors is an integer number (9517682759208).
Almost surely, 2241220433104145 is an apocalyptic number.
It is an amenable number.
241220433104145 is a deficient number, since it is larger than the sum of its proper divisors (215628339337839).
241220433104145 is a wasteful number, since it uses less digits than its factorization.
241220433104145 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 772289094 (or 772289091 counting only the distinct ones).
The product of its (nonzero) digits is 92160, while the sum is 36.
Adding to 241220433104145 its reverse (541401334022142), we get a palindrome (782621767126287).
The spelling of 241220433104145 in words is "two hundred forty-one trillion, two hundred twenty billion, four hundred thirty-three million, one hundred four thousand, one hundred forty-five".
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