Base | Representation |
---|---|
bin | 110110110110101100100101… |
… | …001001000101011110011111 |
3 | 1011122012120202111000101001210 |
4 | 312312230211021011132133 |
5 | 223110143104131403320 |
6 | 2213034112050035503 |
7 | 101546653653222015 |
oct | 6666544511053637 |
9 | 1148176674011053 |
10 | 241253231122335 |
11 | 6a963a145675a3 |
12 | 230845aab78b93 |
13 | a48010b428663 |
14 | 4380a0c1248b5 |
15 | 1cd583bd360e0 |
hex | db6b2524579f |
241253231122335 has 16 divisors (see below), whose sum is σ = 386394680586240. Its totient is φ = 128538553001760.
The previous prime is 241253231122301. The next prime is 241253231122357. The reversal of 241253231122335 is 533221132352142.
It is not a de Polignac number, because 241253231122335 - 27 = 241253231122207 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 241253231122293 and 241253231122302.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 8114792775 + ... + 8114822504.
It is an arithmetic number, because the mean of its divisors is an integer number (24149667536640).
Almost surely, 2241253231122335 is an apocalyptic number.
241253231122335 is a deficient number, since it is larger than the sum of its proper divisors (145141449463905).
241253231122335 is a wasteful number, since it uses less digits than its factorization.
241253231122335 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 16229616278.
The product of its digits is 259200, while the sum is 39.
Adding to 241253231122335 its reverse (533221132352142), we get a palindrome (774474363474477).
The spelling of 241253231122335 in words is "two hundred forty-one trillion, two hundred fifty-three billion, two hundred thirty-one million, one hundred twenty-two thousand, three hundred thirty-five".
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