Base | Representation |
---|---|
bin | 100011000111011111111… |
… | …101010010111000001101 |
3 | 22112200222102121010101212 |
4 | 203013133331102320031 |
5 | 304014300403242313 |
6 | 5044342512344205 |
7 | 336231121615034 |
oct | 43073775227015 |
9 | 8480872533355 |
10 | 2413234040333 |
11 | 8504a07805a6 |
12 | 32b84b245065 |
13 | 14674a8b96bc |
14 | 84b3050171b |
15 | 42b916583a8 |
hex | 231dff52e0d |
2413234040333 has 12 divisors (see below), whose sum is σ = 2563708567680. Its totient is φ = 2271129104832.
The previous prime is 2413234040267. The next prime is 2413234040341. The reversal of 2413234040333 is 3330404323142.
It is a de Polignac number, because none of the positive numbers 2k-2413234040333 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 2413234040333.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2413236040333) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 4235558 + ... + 4771416.
It is an arithmetic number, because the mean of its divisors is an integer number (213642380640).
Almost surely, 22413234040333 is an apocalyptic number.
It is an amenable number.
2413234040333 is a deficient number, since it is larger than the sum of its proper divisors (150474527347).
2413234040333 is a wasteful number, since it uses less digits than its factorization.
2413234040333 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 551476 (or 551459 counting only the distinct ones).
The product of its (nonzero) digits is 62208, while the sum is 32.
Adding to 2413234040333 its reverse (3330404323142), we get a palindrome (5743638363475).
The spelling of 2413234040333 in words is "two trillion, four hundred thirteen billion, two hundred thirty-four million, forty thousand, three hundred thirty-three".
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