Base | Representation |
---|---|
bin | 1110000011000100111… |
… | …0010110010010001101 |
3 | 212001221200100011211221 |
4 | 3200301032112102031 |
5 | 12423233031412303 |
6 | 302512155443341 |
7 | 23302505160244 |
oct | 3406116262215 |
9 | 761850304757 |
10 | 241344013453 |
11 | 93398449464 |
12 | 3a935756551 |
13 | 199b2979c6a |
14 | b976d8995b |
15 | 6427e424bd |
hex | 383139648d |
241344013453 has 2 divisors, whose sum is σ = 241344013454. Its totient is φ = 241344013452.
The previous prime is 241344013409. The next prime is 241344013459. The reversal of 241344013453 is 354310443142.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 181269023049 + 60074990404 = 425757^2 + 245102^2 .
It is a cyclic number.
It is not a de Polignac number, because 241344013453 - 237 = 103905059981 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (241344013459) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 120672006726 + 120672006727.
It is an arithmetic number, because the mean of its divisors is an integer number (120672006727).
Almost surely, 2241344013453 is an apocalyptic number.
It is an amenable number.
241344013453 is a deficient number, since it is larger than the sum of its proper divisors (1).
241344013453 is an equidigital number, since it uses as much as digits as its factorization.
241344013453 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 69120, while the sum is 34.
Adding to 241344013453 its reverse (354310443142), we get a palindrome (595654456595).
The spelling of 241344013453 in words is "two hundred forty-one billion, three hundred forty-four million, thirteen thousand, four hundred fifty-three".
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