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241425513529933 is a prime number
BaseRepresentation
bin110110111001001101000001…
…111110010100001001001101
31011122211001110010202110210211
4312321031001332110021031
5223121003422430424213
62213245203320002421
7101565263200430515
oct6671150176241115
91148731403673724
10241425513529933
116aa1aa9248a337
12230b1a70000411
13a4934361a8285
1443890b2d6a845
151cda071c2a53d
hexdb9341f9424d

241425513529933 has 2 divisors, whose sum is σ = 241425513529934. Its totient is φ = 241425513529932.

The previous prime is 241425513529867. The next prime is 241425513530077. The reversal of 241425513529933 is 339925315524142.

It is a happy number.

241425513529933 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 234231944311044 + 7193569218889 = 15304638^2 + 2682083^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-241425513529933 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (241425513529033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 120712756764966 + 120712756764967.

It is an arithmetic number, because the mean of its divisors is an integer number (120712756764967).

Almost surely, 2241425513529933 is an apocalyptic number.

It is an amenable number.

241425513529933 is a deficient number, since it is larger than the sum of its proper divisors (1).

241425513529933 is an equidigital number, since it uses as much as digits as its factorization.

241425513529933 is an evil number, because the sum of its binary digits is even.

The product of its digits is 34992000, while the sum is 58.

The spelling of 241425513529933 in words is "two hundred forty-one trillion, four hundred twenty-five billion, five hundred thirteen million, five hundred twenty-nine thousand, nine hundred thirty-three".