Base | Representation |
---|---|
bin | 100011010110000000010… |
… | …101010000111001010101 |
3 | 22121012011220201112020201 |
4 | 203112000111100321111 |
5 | 304243200223030432 |
6 | 5055440230300501 |
7 | 340322110540024 |
oct | 43260025207125 |
9 | 8535156645221 |
10 | 2428809580117 |
11 | 857063764128 |
12 | 3328774b7731 |
13 | 148060748a2b |
14 | 857aad428bb |
15 | 432a3c57ee7 |
hex | 23580550e55 |
2428809580117 has 2 divisors, whose sum is σ = 2428809580118. Its totient is φ = 2428809580116.
The previous prime is 2428809580081. The next prime is 2428809580139. The reversal of 2428809580117 is 7110859088242.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2081645869681 + 347163710436 = 1442791^2 + 589206^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2428809580117 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2428809580157) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1214404790058 + 1214404790059.
It is an arithmetic number, because the mean of its divisors is an integer number (1214404790059).
Almost surely, 22428809580117 is an apocalyptic number.
It is an amenable number.
2428809580117 is a deficient number, since it is larger than the sum of its proper divisors (1).
2428809580117 is an equidigital number, since it uses as much as digits as its factorization.
2428809580117 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2580480, while the sum is 55.
The spelling of 2428809580117 in words is "two trillion, four hundred twenty-eight billion, eight hundred nine million, five hundred eighty thousand, one hundred seventeen".
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