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2430212143 = 3263374471
BaseRepresentation
bin1001000011011010…
…0001100000101111
320021100212120100011
42100312201200233
514434113242033
61041051514051
7114136314412
oct22066414057
96240776304
102430212143
111037878397
12579a58927
132c9636368
14190a85b79
15e3542ccd
hex90da182f

2430212143 has 4 divisors (see below), whose sum is σ = 2430319248. Its totient is φ = 2430105040.

The previous prime is 2430212129. The next prime is 2430212149. The reversal of 2430212143 is 3412120342.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 2430212143 - 29 = 2430211631 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2430212149) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4603 + ... + 69868.

It is an arithmetic number, because the mean of its divisors is an integer number (607579812).

Almost surely, 22430212143 is an apocalyptic number.

2430212143 is a deficient number, since it is larger than the sum of its proper divisors (107105).

2430212143 is an equidigital number, since it uses as much as digits as its factorization.

2430212143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 107104.

The product of its (nonzero) digits is 1152, while the sum is 22.

The square root of 2430212143 is about 49297.1818971430. The cubic root of 2430212143 is about 1344.4605462298.

Adding to 2430212143 its reverse (3412120342), we get a palindrome (5842332485).

The spelling of 2430212143 in words is "two billion, four hundred thirty million, two hundred twelve thousand, one hundred forty-three".

Divisors: 1 32633 74471 2430212143