Base | Representation |
---|---|
bin | 10110101001000111… |
… | …110000100111100101 |
3 | 2022202100201202012112 |
4 | 112221013300213211 |
5 | 344242412021013 |
6 | 15100251130405 |
7 | 1520323314155 |
oct | 265107604745 |
9 | 68670652175 |
10 | 24312220133 |
11 | a346683913 |
12 | 4866143a05 |
13 | 23a5bb5396 |
14 | 1268cb0765 |
15 | 974615ba8 |
hex | 5a91f09e5 |
24312220133 has 2 divisors, whose sum is σ = 24312220134. Its totient is φ = 24312220132.
The previous prime is 24312220123. The next prime is 24312220159. The reversal of 24312220133 is 33102221342.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 23342645089 + 969575044 = 152783^2 + 31138^2 .
It is a cyclic number.
It is not a de Polignac number, because 24312220133 - 24 = 24312220117 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 24312220099 and 24312220108.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (24312220123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12156110066 + 12156110067.
It is an arithmetic number, because the mean of its divisors is an integer number (12156110067).
Almost surely, 224312220133 is an apocalyptic number.
It is an amenable number.
24312220133 is a deficient number, since it is larger than the sum of its proper divisors (1).
24312220133 is an equidigital number, since it uses as much as digits as its factorization.
24312220133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 23.
Adding to 24312220133 its reverse (33102221342), we get a palindrome (57414441475).
The spelling of 24312220133 in words is "twenty-four billion, three hundred twelve million, two hundred twenty thousand, one hundred thirty-three".
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